The Formula Of The Area Of A Triangle Is A=1/2bh.

A=1/2bh. Solve for h.. The idea is to isolate the variable h to one side of the equation -- doesn t matter which side.. Starting with: A=1/2bh. Let s start by moving the b . Since b is being "multiplied" to h , to move it, do the opposite operation -- "divide" BOTH sides by b to get:1/2bh÷1/2bh=A÷1/2bh (the 1/2b will cancel with the 1/2b on the left leaving h) h=A*2b New questions in Mathematics The functions f(x) and g(x) are shown on the graph.For each problem there should be a numeric value associated with the "b" in A=1/2bh and the "A" in A=6s^2, In each instance, you would substitute the numeric value for the corresponding letter and...SOlve for h in A= 1/2bh, you get best answer if you help me...Simple and best practice solution for a=1/2bh;b=8,h=16 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework. If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solve the formula for the indicated variable A=1/2bh solve

Solve for h a=1/2bh. Rewrite the equation as . Multiply both sides of the equation by . Simplify . Tap for more steps... Cancel the common factor of . Tap for more steps... Cancel the common factor. Rewrite the expression. Multiply by . Divide each term by and simplify. Tap for more steps...A=1/2bh solve the equasion for h in terms of b and a. Answers: 2 Get Other questions on the subject: Mathematics. Mathematics, 21.06.2019 18:00, ccdarling7185. The only way to identify an intercept is as an ordered pair. true false. Answers: 1. continue. Mathematics, 21.06.2019 20:00, xwalker6772How do you solve for h in #a=1/2bh#? Algebra Linear Equations Formulas for Problem Solving. 1 Answer sjc Dec 26, 2016 #b=(2a)/h# Explanation: rearrange by applying inverse operations. #a=1/2bh# multiply both sides by #2# #2xxa=cancel(1/2xx2)bh# #2a=bh# divide both sides byb #(2a)/h=bcancel(h/h)# #b=(2a)/h#A = 1/2(b1 + b2)h for b1, solve for the specified value

$Solve the formula for the indicated variable A=1/2bh solve$

A=1/2bh solve for h? | Yahoo Answers

A=1/2bh Solve for h.. The idea is to isolate the variable 'h' to one side of the equation -- doesn't matter which side.. Starting with: A=1/2bh. Let's start by moving the 'b'. Since 'b' is being "multiplied" to 'h', to move it, do the opposite operation -- "divide" BOTH sides by 'b' to get: A/b = [1/2bh]/b The 'b's cancel on the right leavingThe formula for the area A of the triangle is A=1/2BH, where B is the length of the base, and H is the height. Solve the equation for B. I don't know how I'm supposed to be able to figure this out?Online math solver with free step by step solutions to algebra, calculus, and other math problems. Get help on the web or with our math app.can you show the steps i really don't get it ! thanks :) Happy Holidays! SOLVE FOR THE VARIABLE INDICATED. A) P = a + b + c for c B) A = 1/2bh for h C) C = 2πr for r D) rt = d for t thanks :)When you have multiple variables, to solve for h just means to get h alone on the left side and some expression on the right side of the equals sign. A = (1/2)bh 2A = bh 2A/b = h

Click here to see ALL issues on Expressions-with-variables Question 157880: A=1/2bhSolve for h. (Scroll Down for Answer!) Did you understand that Algebra.Com has hundreds of free volunteer tutors who help people with math homework? Anyone can ask a math query, and most questions get solutions! OR get fast PAID lend a hand on: Go!!! Found 2 solutions by means of MathLover1, nerdybill:Answer by way of MathLover1(18100) (Show Source): You can put this resolution on YOUR website online! Solve for . ...either side multiply by ....each side divide by means of .........or......... Answer via nerdybill(7384) (Show Source): You can put this resolution on YOUR website! A=1/2bhSolve for h..The idea is to isolate the variable 'h' to at least one side of the equation -- doesn't subject which aspect..Starting with:A=1/2bh.Let's start by means of shifting the 'b'. Since 'b' is being "multiplied" to 'h', to move it, do the opposite operation -- "divide" BOTH aspects by means of 'b' to get:A/b = [1/2bh]/bThe 'b's cancel at the right leaving:A/b = 1/2h.Finally, to transport the 1/2 -- multiply all sides via it is reciprocal -- 2/1:(2/1)[A/b] = (2/1)[1/2h]On the left we get:2A/b = (2/1)[1/2h]On the suitable the 2s and the 1s cancel leaving:2A/b = hThat's it, you are completed..The equation now says, that the peak 'h' is the same as two instances the area 'A' divided through the bottom 'b'. New! FREE algebra solver that shows work: